bf78cfd0-7205-4a08-9a32-c44b7b288283 9 4 5 decimal

&[DATE] &[TIME] - &[FILENAME]

i i 1 n sum Maxima i n *

# MaximaLog Request: sum(%i,i,1,n);
Answer: 
(%o17) %i*n
(%i18) 
Received bytes: 20
SMath get:

Here we have a translation problem with multiple i's

j j 1 n sum Maxima n 1 n + (* 2 /

In Sum() the loop variable is anonymized.

i i 1 n Sum n 1 n + (* 2 /

# MaximaLog Request: sum(LXAXUXFi,LXAXUXFi,1,n);
Answer: 
(%o21) (n^2+n)/2
(%i22) 
Received bytes: 25
SMath get:

j j 1 n Sum n 1 n + (* 2 /

# MaximaLog Request: sum(LXAXUXFj,LXAXUXFj,1,n);
Answer: 
(%o23) (n^2+n)/2
(%i24) 
Received bytes: 25
SMath get:

i i f Maxima i i f

# MaximaLog Request: f(%i,i);
Answer: 
(%o25) f(%i,i)
(%i26) 
Received bytes: 23
SMath get:

When assigning Sum() to sum(), the workaround doesn't work.

a b c d sum a b c d Sum 11 line :

j j 1 n sum j n *

# MaximaLog Request: sum(j,LXAXUXFb,1,n);
Answer: 
(%o27) j*n
(%i28) 
Received bytes: 19
SMath get:

This would be the correct result if i is treated as imaginary unit. In maxima, assignment to %i doesn't change the value

$sum(%i,%i,1,n)$ Maxima i n *

Here we see an example of the translation problem

i i i i i i f Maxima i i i i i i f

# MaximaLog Request: f(%i,i,%i,i,%i,i);
Answer: 
(%o31) f(%i,i,%i,i,%i,i)
(%i32) 
Received bytes: 33
SMath get: