4 5 decimal

&[DATE] &[TIME] - &[FILENAME]

Table Temperature Enthalpy 100 °C * 2676 kJ kg / * 110 °C * 2691.5 kJ kg / * 32 mat :

Ent Table 1 col Table 2 col 378.15 linterp :

Ent #

Don't work with string data in the vector (labels)

Data Table 2312 submatrix :

Data 373.15 K * 2.676 106^* m 2^s 2^/ * 383.15 K * 2.6915 106^* m 2^s 2^/ * 22 mat

Ent Data 1 col Data 2 col 105 °C * linterp :

Ent #

Don't work with units

Ent Data 1 col Data 2 col 378.15 linterp :

Entering temperature in Kelvin (w/o units),it work

Ent 2.6838 106^*

h Ent 103^/ kJ kg / * :

h kJ kg / 2683.75

T.k is divided by K because internally Smath uses Kelvin, if you divide by ºC you'll have a wrong answer

T enthalpy T.k T K / : Data 1 col Data 2 col T.k linterp 103^/ kJ kg / * 21 line :

T.1 105 °C * :

h1 T.1 enthalpy :

h1 2.6838 106^* Gy *

h1 kJ kg / 2683.75

Correct value and unit

Using directly the Table matrix

T enthalpy T.k T K / : Table 2312 submatrix 1 col Table 2312 submatrix 2 col T.k linterp 103^/ kJ kg / * 21 line :

T.2 T.1 :

h2 T.2 enthalpy :

h2 2.6838 106^* Gy *

h2 kJ kg / 2683.75

Correct value and unit