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      <header alignment="Center" color="#a9a9a9">&amp;[DATE] &amp;[TIME] - &amp;[FILENAME]</header>
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    <text lang="eng">
      <p>A long uniform rod of 50-mm diameter with a thermal conductivity of 15 W/m-K is heatedinternally by volumetric energy generation of 20 kW/m3. The rod is positioned coaxiallywithin a larger circular tube of 60-mm diameter whose surface is maintained at 500 degC.The annular region between the rod and the tube is evacuated, and their surfaces arediffuse and gray with an emissivity of 0.2.a) Determine the center and surface temperatures of the rod.b) Determine the center and surface temperatures of the rod if atmospheric air occupiesthe annular space.c) For tube diameters of 60, 100, and 1000 mm and for both the evacuated and atmosphericconditions, compute and plot the center and surface temperatures as a function ofequivalent surface emissivities in the range from 0.1 to 1.0.</p>
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      <p>Given:</p>
    </text>
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        <e type="operand">15</e>
        <e type="operand" style="unit">W</e>
        <e type="operand" style="unit">m</e>
        <e type="operand" style="unit">K</e>
        <e type="operator" args="2">*</e>
        <e type="operator" args="2">/</e>
        <e type="operator" args="2">*</e>
        <e type="operator" args="2">:</e>
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        <e type="operand">q'</e>
        <e type="operand">20</e>
        <e type="operand" style="unit">kW</e>
        <e type="operand" style="unit">m</e>
        <e type="operand">3</e>
        <e type="operator" args="2">^</e>
        <e type="operator" args="2">/</e>
        <e type="operator" args="2">*</e>
        <e type="operator" args="2">:</e>
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        <e type="operand">D.1</e>
        <e type="operand">50</e>
        <e type="operand" style="unit">mm</e>
        <e type="operator" args="2">*</e>
        <e type="operator" args="2">:</e>
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    <math decimalPlaces="3">
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        <e type="operand">T.2</e>
        <e type="operand">773</e>
        <e type="operand" style="unit">K</e>
        <e type="operator" args="2">*</e>
        <e type="operator" args="2">:</e>
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        <e type="operand">T.2</e>
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        <e type="operand" style="unit">°C</e>
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        <e type="operand">499.85</e>
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    <text lang="eng">
      <p>Stefan Boltzmann constant:</p>
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    <math decimalPlaces="3">
      <input>
        <e type="operand">σ</e>
        <e type="operand">5.670400</e>
        <e type="operand">10</e>
        <e type="operand">8</e>
        <e type="operator" args="1">-</e>
        <e type="operator" args="2">^</e>
        <e type="operator" args="2">*</e>
        <e type="operand" style="unit">W</e>
        <e type="operand" style="unit">m</e>
        <e type="operand">2</e>
        <e type="operator" args="2">^</e>
        <e type="operand" style="unit">K</e>
        <e type="operand">4</e>
        <e type="operator" args="2">^</e>
        <e type="operator" args="2">*</e>
        <e type="operator" args="2">/</e>
        <e type="operator" args="2">*</e>
        <e type="operator" args="2">:</e>
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      <input>
        <e type="operand">F.12</e>
        <e type="operand">1</e>
        <e type="operator" args="2">:</e>
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        <e type="operand">A.1</e>
        <e type="operand">π</e>
        <e type="operand">D.1</e>
        <e type="operator" args="2">*</e>
        <e type="operator" args="2">:</e>
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        <e type="operand">0.157</e>
        <e type="operand" style="unit">m</e>
        <e type="operator" args="2">*</e>
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        <e type="operand">D.2</e>
        <e type="function" args="1">A.2</e>
        <e type="operand">π</e>
        <e type="operand">D.2</e>
        <e type="operator" args="2">*</e>
        <e type="operator" args="2">:</e>
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        <e type="operand">T</e>
        <e type="operand">300</e>
        <e type="operand" style="unit">K</e>
        <e type="operator" args="2">*</e>
        <e type="operator" args="2">:</e>
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    <text lang="eng">
      <p>Numerical methods can't handle equals without some symbolic help. Use rhs-lhs = 0 instead. </p>
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        <e type="operand">T</e>
        <e type="operand">ε</e>
        <e type="operand">D.2</e>
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        <e type="operand">T</e>
        <e type="operand">4</e>
        <e type="operator" args="2">^</e>
        <e type="operand">T.2</e>
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        <e type="operator" args="2">^</e>
        <e type="operator" args="2">-</e>
        <e type="bracket">(</e>
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        <e type="operand">ε</e>
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        <e type="operand">1</e>
        <e type="operand">F.12</e>
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        <e type="operator" args="2">+</e>
        <e type="operand">1</e>
        <e type="operand">ε</e>
        <e type="operator" args="2">-</e>
        <e type="operand">ε</e>
        <e type="operand">D.2</e>
        <e type="function" args="1">A.2</e>
        <e type="operator" args="2">*</e>
        <e type="operator" args="2">/</e>
        <e type="bracket">(</e>
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        <e type="operator" args="2">/</e>
        <e type="operand">q'</e>
        <e type="operand">π</e>
        <e type="operand">D.1</e>
        <e type="operand">2</e>
        <e type="operator" args="2">^</e>
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        <e type="operand">4</e>
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        <e type="bracket">(</e>
        <e type="operator" args="2">*</e>
        <e type="operator" args="2">-</e>
        <e type="operator" args="2">:</e>
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    <text lang="eng">
      <p>This setup simulates theparametrization in the Mathcadsolve blocks</p>
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        <e type="operand">ε</e>
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        <e type="operand">D.2</e>
        <e type="operand">60</e>
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        <e type="operand">1</e>
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        <e type="function" args="4">Bisection</e>
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        <e type="operand">1</e>
        <e type="operand">MAXITERS</e>
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        <e type="operand">a</e>
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        <e type="operand">0</e>
        <e type="operator" args="2">&gt;</e>
        <e type="operand">a</e>
        <e type="operand">c</e>
        <e type="operator" args="2">:</e>
        <e type="operand">b</e>
        <e type="operand">c</e>
        <e type="operator" args="2">:</e>
        <e type="function" args="3">if</e>
        <e type="function" args="3">if</e>
        <e type="operand">2</e>
        <e type="operand">1</e>
        <e type="function" args="4">line</e>
        <e type="function" args="3">for</e>
        <e type="operand">c</e>
        <e type="operand">2</e>
        <e type="operand">1</e>
        <e type="function" args="4">line</e>
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        <e type="operand">MAXITERS</e>
        <e type="operand">50</e>
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        <e type="operand">T.1</e>
        <e type="operand">500</e>
        <e type="operand" style="unit">K</e>
        <e type="operator" args="2">*</e>
        <e type="operator" args="2">:</e>
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        <e type="operand">T.1</e>
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        <e type="operand">189.1835</e>
        <e type="operand" style="unit">N</e>
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        <e type="operator" args="2">*</e>
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        <e type="operand">T.2</e>
        <e type="operand">900</e>
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        <e type="operand">112.9434</e>
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        <e type="operator" args="2">*</e>
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        <e type="operand">T</e>
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        <e type="operand">811.748</e>
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    <plot type="2d" render="lines" scale_x="0.0417218199209484" scale_y="23.2095513559791" scale_z="1.38280736220498" rotate_x="0" rotate_y="0" rotate_z="0" transpose_x="-108" transpose_y="-323" transpose_z="0">
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        <e type="operator" args="2">:</e>
        <e type="operand">ε</e>
        <e type="operand">D.2</e>
        <e type="function" args="2">fT</e>
        <e type="function" args="1">vectorize</e>
        <e type="function" args="2">augment</e>
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  <region id="27" left="423" top="855" width="335" height="104" color="#000000" bgColor="#ffffff" fontSize="10">
    <text lang="eng">
      <p>Seems that Newton methods never found a good interval for the roots. Bisection never fails! If the interval T1..T2 isn't enough good for the entire range of ε can use a recursive search of interval values.</p>
    </text>
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