7551e83e-7193-4997-9f09-0dbb32e99f9d 22 4 4 false true 0 0 decimal

&[DATE] &[TIME] - &[FILENAME]

P 14 ton 4 / * g.e * 3 * : 9.341 104^* N *

E.1 200 GPa * :

E.2 200 GPa * :

ν.1 0.28 :

ν.2 0.28 :

α 90 deg * :

R.1' 180 mm * :

R.1 800 mm * :

R.2' 30 mm * :

R.2 100000 m * :

z 10 mm * :

B 14 / 1 R.1 / 1 R.2 / + 1 R.1' / + 1 R.2' / + (* 14 / 1 R.1 / 1 R.1' / - (1 R.2 / 1 R.2' / + (+ (2^41 R.1 / 1 R.1' / - (* 1 R.2 / 1 R.2' / + (* α sin 2^* - sqrt * + : 19.44 1 m / *

A 14 / 1 R.1 / 1 R.2 / + 1 R.1' / + 1 R.2' / + (* 14 / 1 R.1 / 1 R.1' / - (1 R.2 / 1 R.2' / + (+ (2^41 R.1 / 1 R.1' / - (* 1 R.2 / 1 R.2' / + (* α sin (2^* - sqrt * - (: 0.625 1 m / *

B A / 31.11

k' K 11 k' 2^θ sin (2^* - sqrt / θ 0 π 2 / int :

k' E 1 k' 2^θ sin (2^* - sqrt θ 0 π 2 / int :

k Q 1 k 2^/ (k' E * k' K - k' K k' E - / :

k' 1 k 2^- sqrt :

k 0.866 :

0.866 Q 1.241

I want to obtain the K value for a particulat \[REGION[9fa9308db6ef4dfd98844ce58de8a293]]\

B A / relationship *

K k Q k solve : #

As you can see this did not work the example in textbook gave k is 0.866 if b/a is 1.241

Here i re-wrote all the equations to be in terns of k

k K 111 k 2^- (θ sin (2^* - sqrt / θ 0 π 2 / int :

k E 11 k 2^- (θ sin (2^* - sqrt θ 0 π 2 / int :

k Q 1 k 2^/ (k E * k K - k K k E - / B A / - :