9c67205c-1882-4e7f-9152-32c055ea39db 6 4 5 false false 0 decimal

&[DATE] &[TIME] - &[FILENAME]

the function will return the value corresponding to index j (row: j+1), from column k to the last column, and its label (key) tab j k assign.par kk 1 : i k tab cols range key_value kk el tab 1 i el tab j 1 + (i el 12 mat : kk kk 1 + : 21 line for key_value 31 line :

simple function to declare variables key value declare_var key : value num2str concat str2num :

s 1 declare_var 1

s 1

sanity check

s 50 declare_var 50

s 50

franco 125 declare_var 125

franco 125

same funtcion, but with only one input (vector of 2 elements) key_val declare_var key_val 1 el : key_val 2 el num2str concat str2num :

some example matrix, that will displayed as table parameters index a b c 1 1.1 1.2 1.3 2 2.1 2.2 2.3 3 3.1 3.2 3.3 44 mat :

parameters declare_var assign.par parameters declare_var assign.par

filter value frome table:

result parameters 32 assign.par :

result a 3.1 12 mat b 3.2 12 mat c 3.3 12 mat 31 mat

the result is a vector of vectors

result declare_var vectorize 3.1 3.2 3.3 31 mat

a 3.1

b 3.2

vectorize will work fine

c 3.3

key_val declare_vars key_val declare_var vectorize :

but if I try to wrap in a function, it will not work anymore (msg error: argument must be a string)

key_val declare_vars key_val declare_var vectorize 11 line :

to avoid error I need line ()

a b c Clear 1

a #

b #

c #

result declare_vars 3.1 3.2 3.3 31 mat

it seems to work, but of course the variables definition with line is local, so the global variables are not set

a #

b #

c #

the best I can do is a 2 functions approach

result Clear 1

result parameters 11 assign.par : index 112 mat a 1.1 12 mat b 1.2 12 mat c 1.3 12 mat 41 mat

result declare_var vectorize 1 1.1 1.2 1.3 41 mat

index 1

a 1.1

b 1.2

c 1.3

parameters 32 assign.par declare_var vectorize #

this will not work for some reason

f kv parameters 31 assign.par kv declare_var for :

this kinda works, but I still get an error

index 3

a 3.1

b 3.2

c 3.3