If you select matrix Minor from the tool bar you will get the determinate of the minor matrix. Also if you type minor(B,2,3) you get the determinate.



If you type vminor(B,2,3) you get the minor matrix.



But if you look closely they both have the same symbol M23( B ). M is typically the determinate of the minor matrix. Vminor should have a different symbol perhaps VM?

Hello Ed,

I agree with you. The same symbols for the different operators might be a bit confusing.
Here, just from the result one can conclude what has been used (scalar and matrix result)
[MATH=eng]minor(vminor(B,2,3),2,2)=1[/MATH]
[MATH=eng]vminor(vminor(B,2,3),2,2)=mat(1,1,1)[/MATH]
In addition, there might be something like this:
[MATH=eng]M.23(←B^2[/MATH]
[MATH=eng]A.23(←B/2[/MATH]
[MATH=eng]minor(B,2,3)=13[/MATH][MATH=eng]vminor(B,2,3)=mat(1,4,-1,9,2,2)[/MATH][MATH=eng]M.23(=mat(6,67,104,-2,57,76,15,95,159,3,3)[/MATH]
[MATH=eng]alg(B,2,3)=-13[/MATH][MATH=eng]A.23(=mat(0.5,2,3.5,1.5,0,2.5,-0.5,4.5,5.5,3,3)[/MATH]
Generally, literal index might make confusion as well (especially for the beginners). Fortunately, here is a visual difference between subscripts (additional spaces). However, confusion and errors might be introduced if we are not careful enough. Here is a workaround - we can use something like this in these situations:
[MATH=eng]minor(B,(2),(3))=13[/MATH][MATH=eng]vminor(B,(2),(3))=mat(1,4,-1,9,2,2)[/MATH][MATH=eng]alg(B,(3),(3))=-12[/MATH]


Regards,
Radovan

Radovan,

Thanks for the suggestion.