Hello,

It seems that function rank() will fail with Symbolic optimization.

[MATH=eng]S←mat(2,0,2,0,0,0,1,-1,2,5,-1,1,-2,-3,0,-2,-2,0,0,-6,0,0,0,6,6,0,0,0,-4,-4,6,5)[/MATH]
[MATH=eng]N.r←rank(S)[/MATH]
Symbolic:
[MATH=eng]N.r=0[/MATH]
Numeric:
[MATH=eng]N.r=3[/MATH]
None:
[MATH=eng]N.r=3[/MATH]

Regards,
Radovan

Hello,

Rather strange! Please look at this picture:


And the associate SMath file rank.sm

Could someone read this SMath file and check it out, please. Compare it to the picture above obtained from my computer.
Why the rank is different for matrix S but the same for matrix A by using different Optimization?

Regards,
Radovan

Hi,

I've the same problem using your file... the problem seems to be the matrix dimension (S is 6x5 matrix, A is 5x5 matrix... if you enlarge S adding a new column the difference disappears)


regards

w3b5urf3r

Wrote

I've the same problem using your file... the problem seems to be the matrix dimension (S is 6x5 matrix, A is 5x5 matrix... if you enlarge S adding a new column the difference disappears)

You are right, thank you.

The same happened when we "shrink" the matrix A into the 5x4 matrix. On the other hand rank(A)= 0 only for A equals to zero matrix:

[MATH=eng]rank(mat(0,0,0,0,0,0,2,3))=0[/MATH]

Nevertheless, it should not be this way - the rank of a matrix should not depend on the Optimization applied. There are some other questionable situations where the result is a zero matrix (all zero values in Jacobain matrix and Symbolic optimization, for example- probabelly a bug as well). I suppose this one is a bug too.

Regards,
Radovan

Thank you! Fixing...

Fixed.