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Help! Having problems with solve function - Messages
#1 Posted: 11/23/2014 12:49:08 AM
I'm trying to solve this equation:
3t^3-2t+5=0 using the solve function
solve(3t^3-2t+5=0,t)
but when I type t= to solve it, it doesnt give me an answer, just t= the black box
And yes, I am using the Boolean in the equation and in solve so I honestly don't know what's wrong? It won't give me the answers for any solve questions!
Please help ASAP!
Thanks in advance
3t^3-2t+5=0 using the solve function
solve(3t^3-2t+5=0,t)
but when I type t= to solve it, it doesnt give me an answer, just t= the black box
And yes, I am using the Boolean in the equation and in solve so I honestly don't know what's wrong? It won't give me the answers for any solve questions!
Please help ASAP!
Thanks in advance

#2 Posted: 11/23/2014 1:51:32 AM
Use 3*t, not 3t
С уважением,
Михаил Каганский
#3 Posted: 11/23/2014 6:46:27 AM
#4 Posted: 11/23/2014 7:18:47 AM
WroteYou are not familiar with Smath. The * is inserted automatically when typing.
Are you sure?
Just try to paste the OP code to SMath, and see that 3t is inserted as is, not like "3*t". The thing you mention only applies to interactive typing. OP hasn't specified the method he used in the first place.
If used properly, everything works without maxima:
solve((3*t)^3-2*t+5≡0,t)=-0.6132
С уважением,
Михаил Каганский
#5 Posted: 11/23/2014 4:57:52 PM
sorry I missed the square three which makes everything much easier.
#6 Posted: 11/23/2014 9:06:55 PM
Wrote
solve(3t^3-2t+5=0,t)
but when I type t= to solve it, it doesnt give me an answer, just t= the black box
I'm afraid I didn't understand your problem the first time.
I suppose you do the following:
type "solve(3t^3-2t+5=0,t)"
go to new line
type "t="
and wait for the answer.
That's not correct. solve is not a procedure that modifies its argument t; it is a function that returns a number, ant that number may (or may not) be assigned to a variable.
You need to have the following:
"t:=solve(3*t^3-2*t+5=0,t)"
then your "t=" will give you the answer (in this form, it will be 2.743).
С уважением,
Михаил Каганский
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