IsString() and user functions - Messages
WroteHi,
I found this bug defining user functions with IsString()
The issue disappear using IsString inside line()
regards,
w3b5urf3r
I'm not sure whether this is a bug or a delayed-evaluation 'feature' of using/not-using the program line. I raised a similar question about a month ago ...
WroteHello,
How is the equality (ctl-=) operator supposed to work? I get ([1]=1)=1 but ([1])=2; the latter I expect, but I am surprised that a matrix is equal to a scalar, even though it is just a single element matrix.
Is there a way of programmatically distinguishing between a scalar and an array? I know there's no IsScalar or IsArray function. I've seen the workaround for using num2str & mat and I've written a function
IsArray(x):=
|n:=findstr(num2str(x),"mat" )
|n<>-1
(why doesn't IsArray(x):=findstr(num2str(x),"mat" )<>-1 work?)
, but this would appear to impose quite an evaluation overhead for large matrices. I was hoping to use x=stack(x) to check if x was an array, hence the purpose of my original question.
Stuart
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