for loop counter

for loop counter - Сообщения

#1 Опубликовано: 11.10.2017 14:17:44
timgow

timgow

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Hi,
I wish to loop through the YR formula, in pic below, for values of z being 0,0.2,0.4,0.6,0.8,1.0,1.2,1.4,1.589.
My progress so far is to produce an array evenly spaced z values and if the 1.0001 factor is not applied to hc_full then the last element of the z array is 1.362, rather than 1.589.
It is obvious to me that I have some missing skill here, please throw me some hints.
graph.JPG
Regards, Tim
#2 Опубликовано: 11.10.2017 15:25:59
Jean Giraud

Jean Giraud

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Just define your 'x' vector of values, include in small loop.

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#3 Опубликовано: 11.10.2017 15:49:55
timgow

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Hi Jean,
Thank you for the example file, I will study this for better understanding.
I have longer arrays to create also so wish to automate; if I make z as in the pic or with equal spacing, is there a means of appending the final (1.589) value to the end of the array?
Tim
#4 Опубликовано: 11.10.2017 17:42:16
CBG

CBG

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I do not see any problem.

hc_full.png
#5 Опубликовано: 11.10.2017 22:22:09
Jean Giraud

Jean Giraud

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Wrote

I have longer arrays to create also so wish to automate;



If you have longer array, equally spaced => as easy.
Naturally, if not equally spaced, must be manual.

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#6 Опубликовано: 11.10.2017 22:28:28
Jean Giraud

Jean Giraud

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... if they are not equally spaced, but if there is a bit
of logic in the spacing, we can select from a list that
can be made/refactored as you wish at will from a little
counter loop.
#7 Опубликовано: 12.10.2017 05:28:21
timgow

timgow

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Jean,
Thank you for the counter loop example, this will stretch my programming comprehension.

CBG,
Thank you for typing the work from scratch, and showing no issue with the 1.589 value.
I redefined hc_full immediately above the z range call and then the output changed to match your results.

The hc_full is defined with an if statement.
Capture1a.JPG

The 1.589 value is absent from the z range.
Capture1.JPG

The hc_full is redefined directly above the z range call (to override the value produced by the if statement) and the 1.589 value is now present in the z range.
Capture2.JPG

Have I contravened a working principle in some way?

Tim
#8 Опубликовано: 12.10.2017 05:38:09
timgow

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Redefining hc_full using hc_full:=hc_full also fixes the z range array.
Tim
#9 Опубликовано: 12.10.2017 13:05:33
Jean Giraud

Jean Giraud

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Wrote

Have I contravened a working principle in some way?



Maybe not ? work sheet would help and no help.
Smath 6179 does not take index on the RHS.

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#10 Опубликовано: 12.10.2017 17:45:07
Martin Kraska

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for(3)-loops with initial, second and maximum value aren't robust if floating point values are specified. The internal representation of such numbers may differ from what is displayed due to round-off.

Due to this it is not good programming style to test the equality of two floating point numbers without specifying a tolerance. If you want to be safe, you either introduce such a tolerance or you generate the list of values based on a list of integers.

It should be possible to modify for(3) such that the tolerance is generated as a fraction of the difference between first and second value.

2017-10-12 22_36_42-SMath Studio - [Blatt4_].png
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#11 Опубликовано: 12.10.2017 22:12:01
Jean Giraud

Jean Giraud

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True Martin: that damned floating point often creates a very small imaginary.
#12 Опубликовано: 12.10.2017 23:22:25
Jean Giraud

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In the context of this topic, there was an example in Mathcad 8.
About solving an RK DE relative to "Orbit" by Steven Finch.
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