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Working with Units - Сообщения
#1 Опубликовано: 23.08.2010 19:00:11
Could I ask if there is a way to choose a preferred unit after the program has calculated it?
For eg. the default unit for force is in Newtons ('N). If we wish for this to be displayed as kiloNewton (ie., kN) - how should I do this?
Thanks.
For eg. the default unit for force is in Newtons ('N). If we wish for this to be displayed as kiloNewton (ie., kN) - how should I do this?
Thanks.
#2 Опубликовано: 23.08.2010 19:28:23
#3 Опубликовано: 07.09.2010 13:38:59
"Unit" it's a great feature: they are everywhere in my job
But I've a little issue: how can SMath understand when I want to express a Moment instead of an Energy?
e.i. I need N*m instead Joule J.
Thanks again for this cool software!

But I've a little issue: how can SMath understand when I want to express a Moment instead of an Energy?
e.i. I need N*m instead Joule J.
Thanks again for this cool software!

#4 Опубликовано: 07.09.2010 15:01:09
Hello,
I did not quite understand, sorry. Do you actually want insted of J every result to give you N*m ?. What's wrong with the explanation Andrey gave in the previous post - with the picture included - how to change the unit of the result?. Just change J into N*m.
You might even define a new, say, Nm unit like
'Nm:='N*'m or 'Nm:='J
and every J unit replace with Nm unit.
Regards,
Radovan
WroteBut I've a little issue: how can SMath understand when I want to express a Moment instead of an Energy?
e.i. I need N*m instead Joule J.
I did not quite understand, sorry. Do you actually want insted of J every result to give you N*m ?. What's wrong with the explanation Andrey gave in the previous post - with the picture included - how to change the unit of the result?. Just change J into N*m.
You might even define a new, say, Nm unit like
'Nm:='N*'m or 'Nm:='J
and every J unit replace with Nm unit.
Regards,
Radovan
When Sisyphus climbed to the top of a hill, they said: "Wrong boulder!"
#5 Опубликовано: 07.09.2010 16:09:22
Thanks Radovan for the prompt reply!
I know: it's a subtle question.
J and N*m seem equals but they are quite different: the first referes to energy, the second to an applied load.
Maybe the following link could clarify the concept: http://en.wikipedia.org/wiki/Newton_metre
In the above link they suggest to use J/rad as an alternate unit for torque but it seems that doesen't work on SMath.
How can I solve this issue?
Thanks for the patience.
Regards,
Matteo.
I know: it's a subtle question.
J and N*m seem equals but they are quite different: the first referes to energy, the second to an applied load.
Maybe the following link could clarify the concept: http://en.wikipedia.org/wiki/Newton_metre
In the above link they suggest to use J/rad as an alternate unit for torque but it seems that doesen't work on SMath.

How can I solve this issue?
Thanks for the patience.
Regards,
Matteo.
#6 Опубликовано: 07.09.2010 16:40:39
A picture is worth a thousand words:

click on the placeholder on the right and press the apostrophe " ' " to insert a unit:

type in "N * m" (use the dynamic help to make sure you are using the predefined units):

that should give you the units you desire:


click on the placeholder on the right and press the apostrophe " ' " to insert a unit:

type in "N * m" (use the dynamic help to make sure you are using the predefined units):

that should give you the units you desire:

Will Massie
Mechanical Engineer
Oregon, USA
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Radovan Omorjan 09.09.2010 10:05:00
#7 Опубликовано: 07.09.2010 18:07:50
Yes! It's what I was looking for!
Thank you Will!
Sorry if bothered you guys, I'd never thought that the solution would be so simple.
Br,
Matteo.
Thank you Will!
Sorry if bothered you guys, I'd never thought that the solution would be so simple.
Br,
Matteo.
#8 Опубликовано: 28.09.2019 19:17:24
Hello, I would like to consult you
I define a temperature in degrees Centigrade, when I call it it looks like Kelvin degrees and then I can't make a sum because it tells me they are two different units. How can I do so that the defined temperature is maintained in every calculation in the unit that defined it?
Attached image capture of the problem.
Thank you

I define a temperature in degrees Centigrade, when I call it it looks like Kelvin degrees and then I can't make a sum because it tells me they are two different units. How can I do so that the defined temperature is maintained in every calculation in the unit that defined it?
Attached image capture of the problem.
Thank you
#9 Опубликовано: 29.09.2019 04:22:37
Hello,
There are many posts on the Forum about handling tempereture units. See for example this one.
Regards,
Radovan
There are many posts on the Forum about handling tempereture units. See for example this one.
Regards,
Radovan
When Sisyphus climbed to the top of a hill, they said: "Wrong boulder!"
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frapuano 29.09.2019 08:28:00
#10 Опубликовано: 29.09.2019 07:46:27
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frapuano 29.09.2019 08:28:00
#11 Опубликовано: 29.09.2019 09:37:54
Visit Colebrook, suggestive how to carry Engineering projects.
And recover units in the results. Each project is specific.
Please, feel free to attach your project for more doctoring.

Inst_Colebrook Pipe Data.sm (61 КиБ) скачан 29 раз(а).
And recover units in the results. Each project is specific.
Please, feel free to attach your project for more doctoring.
Inst_Colebrook Pipe Data.sm (61 КиБ) скачан 29 раз(а).
#12 Опубликовано: 29.09.2019 11:30:41
#13 Опубликовано: 29.09.2019 17:11:19
Wrotethanks to everyone!
... too much stuff is missing
#14 Опубликовано: 29.09.2019 19:03:50
#15 Опубликовано: 29.09.2019 22:06:13
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