Hello,

The calculation with units:
T1=25 C T2=0 C I1=10 A

I2:=[2^((T2-T1)/10)]*I1

I1=9.41 A

WHILE without units:
[2^((25-0)/10)]*10= 1.77


Any idea?
Thanks,
Basile

it's not a bug

the problem is that you are using Celsius instead of Kelvin

smath work with kelvin and do (correctly):

[2^(((0+273.15)-(25+273.15))/(10+273.15))]*10=9.41

because the means of the formula that you wrote is [2^(ΔT/T)]*I and work (even without smath) differently with Celsius and Kelvin


this work in the same way with Celsius and Kelvin: [2^(ΔT1/ΔT2)]*I (where ΔT2 in your example may be: 10°C-0°C)


(sorry for my english :blush