Hello everybody.
I can't understand why the phi function does not compare in the graph.
This function is the derivative of the phi function that instead appears in the graph.
Someone could help me please?
Thanks in advance
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Wrote

I can't understand why the phi function does not compare in the graph.
This function is the derivative of the phi function that instead appears in the graph.

1. your φ(t) plots correct
2. The Smath derivative operator works on derivative rules.
3. The φ(t) is too much a monkey business for derivative rules.
4. Rescue via transit infinitesimal analysis.
5. Your constrain in plot argument is obsolete since if/otherwise
was introduced by Davide from f(x) menu "cases".

Derivate (1 doctored).sm (24 КиБ) скачан 38 раз(а).

Thanks for the reply, I solved this problem.
Now, however, an error appears that does not make me draw a graph.
the error says: "The result is higher than the maximum positive value allowed"
what does it mean?

curvatura.sm (48 КиБ) скачан 31 раз(а).

Wrote

Now, however, an error appears that does not make me draw a graph.
the error says: "The result is higher than the maximum positive value allowed"
what does it mean?

... doctored version works top2bottom
1. Remember λ(x) as used
2. More problem(s) ... return the doctored version.
3. Delete all the black

curvatura (1 doctored).sm (53 КиБ) скачан 37 раз(а).

Wrote

Thanks for the reply, I solved this problem.
Now, however, an error appears that does not make me draw a graph.
the error says: "The result is higher than the maximum positive value allowed"
what does it mean?

curvatura.sm (48 КиБ) скачан 31 раз(а).

Hi. Means that' you have divide by zero or something other invalid operation. You must to avoid that for plots with restrictions in the ranges, or with try ... on error in a routine for range plots. Attached have this second option.

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Best regards.
Alvaro.

This technique enable the view of symbolics.

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Best regards.
Alvaro.