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CoolProp units - Getting 'strange' units and can't override them - Сообщения
#1 Опубликовано: 01.08.2017 07:43:27
Hi all ,
I'm putting together a sheet using the CoolProp wrapper
It generally works really well except for the following
Where I'm getting strange units for the Specific Heat capacity of Air
I've tried overriding the units but still don't get what I want (J/kg/K)
I've attached an extract from the sheet --> UnitsProblem.sm (7 КиБ) скачан 94 раз(а).
Probably a really simple answer but I can't seem to find it !!

I'm putting together a sheet using the CoolProp wrapper
It generally works really well except for the following
Where I'm getting strange units for the Specific Heat capacity of Air
I've tried overriding the units but still don't get what I want (J/kg/K)
I've attached an extract from the sheet --> UnitsProblem.sm (7 КиБ) скачан 94 раз(а).
Probably a really simple answer but I can't seem to find it !!

Peter J Francis
Twitter: @PeterJFrancis
Thermal Engineer , Maker , Pilot
#2 Опубликовано: 01.08.2017 09:37:11
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Peter J Francis 02.08.2017 05:18:00
#3 Опубликовано: 01.08.2017 17:05:37
Can't reproduce either "Units don't match",
because there is NO heat capacity unit in Smath.
because there is NO heat capacity unit in Smath.
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Peter J Francis 02.08.2017 05:18:00
#4 Опубликовано: 01.08.2017 18:52:12
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Peter J Francis 02.08.2017 05:18:00
#5 Опубликовано: 02.08.2017 05:28:04
Thanks All,
You are all correct (I knew the answer was going to be obvious ) , pasting in the units J/kg K works fine
Its just that Gy/K seems an odd default unit
Thanks for your help
Peter
You are all correct (I knew the answer was going to be obvious ) , pasting in the units J/kg K works fine
Its just that Gy/K seems an odd default unit
Thanks for your help
Peter
Peter J Francis
Twitter: @PeterJFrancis
Thermal Engineer , Maker , Pilot
#6 Опубликовано: 04.12.2017 16:09:32
hey fellows, how do I calculate WET steam properties through this extension,lets suppose at 16Bar Pressure & 0.7 quality 7 which IFP standard is currently being used?
#7 Опубликовано: 05.12.2017 10:27:10
Wrotehow do I calculate WET steam properties through this extension,lets suppose at [b]16Bar Pressure
Good question. The vapor phase is dry and properties don't change.
That portion of water that drags at the bottom of piping must be
taken into account for massflow calculation.
At the speed steam flows, better be dry. If not => will destroy
my control valves. Puzzling question ?
#8 Опубликовано: 05.12.2017 11:17:30
WroteWrotehow do I calculate WET steam properties through this extension,lets suppose at [b]16Bar Pressure
Good question. The vapor phase is dry and properties don't change.
That portion of water that drags at the bottom of piping must be
taken into account for massflow calculation.
At the speed steam flows, better be dry. If not => will destroy
my control valves. Puzzling question ?
The property(s) that does change when you add water to steam is NOT its pressure or temperature but its enthalpy ...the most major parameter which defines the amount of work that can be extracted
Yes wet steam at very high velocities can be micro bullets for control valves & turbine blades causing erosion
#9 Опубликовано: 05.12.2017 12:00:21
WroteThe property(s) that does change when you add water to steam is NOT its pressure or temperature but its enthalpy ...the most major parameter which defines the amount of work that can be extracted
Yes wet steam at very high velocities can be micro bullets for control valves
Worst than erosion => cavitation.
Can't help more. Steam out of the balloon is dry, isn't ?
If you have wet steam out of the balloon, you have a serious level control problem.
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