Help equation Solution

Help equation Solution - solve equation - Сообщения

#1 Опубликовано: 18.04.2020 07:24:19
Elton

Elton

0 сообщений из 3 понравились пользователям.

Группа: User

I can't solve the equation below, I tried two options but none worked. Someone could help?

Best regards

Elton Freitas

help.png
#2 Опубликовано: 18.04.2020 07:42:44
Jean Giraud

Jean Giraud

983 сообщений из 6866 понравились пользователям.

Группа: User

Wrote

I can't solve the equation below, I tried two options but none worked. Someone could help ?


Please: attach the document for the missing data.

Jean
#3 Опубликовано: 18.04.2020 11:20:12
sergio

sergio

115 сообщений из 329 понравились пользователям.

Группа: User

Let's start by observing that:
1) the "solve" function is native to smath but does not accept units of measurement (if you want to use it you must temporarily get rid of the units of measurement)
2) the "FindRoot" function you have defined relies on "solve" (see above)
3) in the "nonlinear Solver" plugin you will find a "FindRoot" function that can do for you and that manages the units of measurement
4) there are other features and plugins that can help you. I suggest you also consult Martin Kraska's Interactive SMath Handbook with lots of information and practical examples (you can find it in the tool you use to install plugins)

sergio
#4 Опубликовано: 18.04.2020 13:23:01
Elton

Elton

0 сообщений из 3 понравились пользователям.

Группа: User

Yes. It is attached or attached.Modelo_Planilha de Calculos_OM_rev02.sm (2 МиБ) скачан 35 раз(а).

Thank you.

Best Regard.

Elton Freitas
#5 Опубликовано: 18.04.2020 14:11:13
haweHofmann

haweHofmann

3 сообщений из 32 понравились пользователям.

Группа: User


a quadratic equation, solved algebraically?

MPa^2=((σ.solda)/(a.cordao))^(2)+3*((P.total)/(2*h*a.cordao))^(2)

===>

sys(a.cordao≡-sqrt(4*h^2*σ.solda^2+3*P.total^2)/{2*MPa*h},a.cordao≡sqrt(4*h^2*σ.solda^2+3*P.total^2)/{2*MPa*h},2,1)
  • Новые сообщения Новые сообщения
  • Нет новых сообщений Нет новых сообщений