BUG? defining function with "if" and plotting

BUG? defining function with "if" and plotting - Сообщения

#1 Опубликовано: 08.10.2009 20:42:13
Radovan Omorjan

Radovan Omorjan

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Please look at the picture:


When the function is defined with "if" then it can not be plotted together with the matrix M (M - not defined??). Bug, I suppose?

Regards,
Radovan

P.S. Andrey, I think you've sent me recently some pictures with "if" defined functions. As I remember, plotting of those functions has been resolved. Might this be connected?
When Sisyphus climbed to the top of a hill, they said: "Wrong boulder!"
#2 Опубликовано: 26.10.2009 08:34:44
Radovan Omorjan

Radovan Omorjan

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Группа: Moderator

Hello,

Considering the plotting functions (defined with "if" ) and two-column matrices here is a continued discussion about that. It seems that the "if" will not work but the function defined via relation operation will work. Here is the picture

The two plots should be basically the same. Here the plot on the right is Ok, and on the left is not working. Pay attention that the plotting has been fixed in v0.85_3578 (see here )
The same problem will be wrong in v0.85_3545

BTW, it seems that the integration of noncontinous functions will work when defined with relational operators (see the example)

Regards
Radovan
When Sisyphus climbed to the top of a hill, they said: "Wrong boulder!"
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