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Hello,
unfortunately, I can't find the error myself. Why VS(t) and VRG58(t) work well, but V1(t):=VS(t)-VRG58(t) not?
Regards Andreas
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unfortunately, I can't find the error myself. Why VS(t) and VRG58(t) work well, but V1(t):=VS(t)-VRG58(t) not?
Regards Andreas
Auszug.pdf (114,69 КиБ) скачан 62 раз(а).
Auszug.sm (16,52 КиБ) скачан 40 раз(а).
Thanks Sergio,
wrong was VRG58(t):=Ig(t)*(1/ZLRG58+1/RRG58)
right is VRG58(t):=Ig(t)*(ZLRG58+RRG58)
Regards Andreas
wrong was VRG58(t):=Ig(t)*(1/ZLRG58+1/RRG58)
right is VRG58(t):=Ig(t)*(ZLRG58+RRG58)
Regards Andreas
Hello,
and here’s another problem. Why does the differential of V1(t) work, but not that of V2(t)?
Both are sine functions; later, I’d like to try using square-wave functions as input as well.
For V1 and V2, I need the peak-to-peak amplitude and the phase difference between the two. I want to see if I can get better approximations for determining C1 by taking RG58 and the probe tip’s internal resistance into account in the measurement results.
Regards Andreas
Translation of “Der Wert ist oberhalb der maximalen Grenze für positive Zahlen” = “The value is above the maximum limit for positive numbers”
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and here’s another problem. Why does the differential of V1(t) work, but not that of V2(t)?
Both are sine functions; later, I’d like to try using square-wave functions as input as well.
For V1 and V2, I need the peak-to-peak amplitude and the phase difference between the two. I want to see if I can get better approximations for determining C1 by taking RG58 and the probe tip’s internal resistance into account in the measurement results.
Regards Andreas
Translation of “Der Wert ist oberhalb der maximalen Grenze für positive Zahlen” = “The value is above the maximum limit for positive numbers”
Versuch mit R und C mit Oszi.pdf (982,36 КиБ) скачан 45 раз(а).
Versuch mit R und C mit Oszi.sm (131,13 КиБ) скачан 50 раз(а).Отредактировано 10.05.2026 06:01:03
Yeah, that's how it works for me, too.
It's me again, with a new problem.
Why doesn't the last line work, when the four lines above it do?
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Why doesn't the last line work, when the four lines above it do?
Versuch mit R und C mit Oszi Auszug.pdf (910,43 КиБ) скачан 28 раз(а). Versuch mit R und C mit Oszi Auszug.sm (130,35 КиБ) скачан 19 раз(а).Hi. I have no idea why it fails, however this may be a workaround, consisting of directly applying the Newton-Raphson method.

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Best regards.
Alvaro.

Versuch mit R und C mit Oszi Auszug.sm (121,16 КиБ) скачан 9 раз(а).
Best regards.
Alvaro.
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