Anwer continuing into next equation - Сообщения
#1 Опубликовано: 28.09.2010 22:48:57
Hi all can someone point me in the right direction
how do I get the answer from one equation , to be used by another , for example a=2 b=3 axb=?
this software looks good and runs on Ubuntu 10.10 a treat
thanks
Stephen
how do I get the answer from one equation , to be used by another , for example a=2 b=3 axb=?
this software looks good and runs on Ubuntu 10.10 a treat
thanks
Stephen
#2 Опубликовано: 29.09.2010 02:33:41
Hello Stephen,
I do not understand your question.
Could you be more specific please?
Regards,
Radovan
I do not understand your question.
Could you be more specific please?
Regards,
Radovan
When Sisyphus climbed to the top of a hill, they said: "Wrong boulder!"
#3 Опубликовано: 29.09.2010 10:22:17
I think like this
a:=2
a=2
b:=3
b=3
c:=a+b
c=5
d:=a+c
d=7
Peter
a:=2
a=2
b:=3
b=3
c:=a+b
c=5
d:=a+c
d=7
Peter
#4 Опубликовано: 30.09.2010 03:19:34
Hello,
Do not forget that you do not need to put these regions in that particular order.
In SMath this is quite possible:
[MATH]d←a+c[/MATH]
[MATH]c←a+b[/MATH]
[MATH]a←2[/MATH]
[MATH]b←3[/MATH]
[MATH]d=7[/MATH]
[MATH]c=5[/MATH]
[MATH]a←10[/MATH]
[MATH]b←15[/MATH]
[MATH]c=25[/MATH]
[MATH]d=35[/MATH]
Regards,
Radovan
Do not forget that you do not need to put these regions in that particular order.
In SMath this is quite possible:
[MATH]d←a+c[/MATH]
[MATH]c←a+b[/MATH]
[MATH]a←2[/MATH]
[MATH]b←3[/MATH]
[MATH]d=7[/MATH]
[MATH]c=5[/MATH]
[MATH]a←10[/MATH]
[MATH]b←15[/MATH]
[MATH]c=25[/MATH]
[MATH]d=35[/MATH]
Regards,
Radovan
When Sisyphus climbed to the top of a hill, they said: "Wrong boulder!"
#5 Опубликовано: 30.09.2010 20:48:15
Thats it thanks, off and running now , thank you all for the swift response !
Stephen
Stephen
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