Treatment of imaginary unit - Сообщения
#1 Опубликовано: 27.02.2012 13:24:35
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Hello,
It seems that the imaginary unit (i = sqrt(-1)) is treated differently in v0.92 comparing to v0.91. It seems it is not allowed as a function argument in the function definition.
Example:
Accompanied file i-funargument.sm
Regards,
Radovan
It seems that the imaginary unit (i = sqrt(-1)) is treated differently in v0.92 comparing to v0.91. It seems it is not allowed as a function argument in the function definition.
Example:
Accompanied file i-funargument.sm
Regards,
Radovan
When Sisyphus climbed to the top of a hill, they said: "Wrong boulder!"
#2 Опубликовано: 27.02.2012 15:06:48
Yes. This is by design: "i" (imaginary part) cannot be used as an attribute of the function definition anymore.
This was required to fix the situation we had in earlier SMath Studio versions:
Regards.
This was required to fix the situation we had in earlier SMath Studio versions:
Regards.
#3 Опубликовано: 27.02.2012 15:22:30
325 сообщений из 2 052 понравились и 1 не понравились пользователям.
Группа: Moderator
Thank you Andrey,
Yes, I remembered now the discussion about the imaginary unit as a function argument.
Regards,
Radovan
Yes, I remembered now the discussion about the imaginary unit as a function argument.
Regards,
Radovan
When Sisyphus climbed to the top of a hill, they said: "Wrong boulder!"
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