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How to use for-loop inside a function - Can't figure out the syntax - Messages
#1 Posted: 3/19/2018 7:11:17 AM
#2 Posted: 3/19/2018 7:49:55 AM
Hi Mikko
The loop syntax needs tweaking, and the output variable needs to be defined. The attached file works for me.
kertoimetTest.sm (4 KiB) downloaded 118 time(s).
Hope this helps.
Brian
The loop syntax needs tweaking, and the output variable needs to be defined. The attached file works for me.
kertoimetTest.sm (4 KiB) downloaded 118 time(s).
Hope this helps.
Brian
2 users liked this post
#4 Posted: 3/19/2018 9:53:50 AM
Greetings
I have not been able to understand the purpose for which the imagined algorithm is used. As the question arises, it is a case of express identification of a certain value in the "kertoimet" matrix. In this case in 99.99 (9 ...) of cases, the result will be an error. If so then you can avoid ambiguity using the first procedure (case identification) in the attached file. Looking at the problem in terms of practical use, in the first column of the "kertoimet" matrix there are some non-dimensional coefficients corresponding to circular x-ray surfaces with the area expressed in square millimeters. In this case, a linear interpolation of these coefficients would be useful depending on the radius of the circle, and the procedure is the one presented in the case of interpolation.
Imagination.sm (6 KiB) downloaded 54 time(s).
I have not been able to understand the purpose for which the imagined algorithm is used. As the question arises, it is a case of express identification of a certain value in the "kertoimet" matrix. In this case in 99.99 (9 ...) of cases, the result will be an error. If so then you can avoid ambiguity using the first procedure (case identification) in the attached file. Looking at the problem in terms of practical use, in the first column of the "kertoimet" matrix there are some non-dimensional coefficients corresponding to circular x-ray surfaces with the area expressed in square millimeters. In this case, a linear interpolation of these coefficients would be useful depending on the radius of the circle, and the procedure is the one presented in the case of interpolation.
Imagination.sm (6 KiB) downloaded 54 time(s).
#5 Posted: 3/19/2018 6:16:29 PM
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