Infinite loop problem? - Сообщения
#1 Опубликовано: 06.08.2010 17:05:07
Hello Andrey,
I think this should be a bug.
[MATH]f(x)←5+f(x)[/MATH]
[MATH]f(1)=#[/MATH]
This will not stop executing until it is interrupted. I think this is an infinite loop problem.
Regards,
Radovan
I think this should be a bug.
[MATH]f(x)←5+f(x)[/MATH]
[MATH]f(1)=#[/MATH]
This will not stop executing until it is interrupted. I think this is an infinite loop problem.
Regards,
Radovan
When Sisyphus climbed to the top of a hill, they said: "Wrong boulder!"
#2 Опубликовано: 06.08.2010 20:18:55
Hello.
Thank you. Will check this later.
Regards.
Thank you. Will check this later.
Regards.
#3 Опубликовано: 18.08.2010 06:55:06
what behaviour would you expect?
you are asking for 5+5+5....
you are asking for 5+5+5....
#4 Опубликовано: 18.08.2010 07:27:35
what behaviour would you expect?
you are asking for 5+5+5....
Yes, Greg, that is the problem. We can have something like this:
[MATH lang=eng]f(x)←x[/MATH]
[MATH lang=eng]f(x)←f(x)/2[/MATH]
[MATH lang=eng]f(5)=2.5[/MATH]
But with this, we get in trouble.
[MATH lang=eng]f(x)←f(x)/2[/MATH]
[MATH lang=eng]f(5)=#@#[/MATH]
The question is - Does it to be the user's problem to interrupt such a calculation or to suppress it by an error message? I was not sure about it, and that was my doubt about "endless loop".
Regards,
Radovan
When Sisyphus climbed to the top of a hill, they said: "Wrong boulder!"
#5 Опубликовано: 29.09.2010 18:11:03
Fixed.
#6 Опубликовано: 30.09.2010 03:10:33
Hello Andrey,
Sorry for being persistent, but I think I was not precise enough. The previous calculation will work in SMath - there was not a problem.
But, try this:
The problem is that this will never stop, until we "Interrupt processing". My question was - Should it be left this way or should it be stopped by SMath.
Regards,
Radovan
Sorry for being persistent, but I think I was not precise enough. The previous calculation will work in SMath - there was not a problem.
But, try this:
The problem is that this will never stop, until we "Interrupt processing". My question was - Should it be left this way or should it be stopped by SMath.
Regards,
Radovan
When Sisyphus climbed to the top of a hill, they said: "Wrong boulder!"
#7 Опубликовано: 30.09.2010 08:52:55
This is also fixed. Now SMath Studio understands that it is not good practice to repeat substitution of the already substituted functions with the same names 
So one will not see infinite loops in such cases anymore.
Regards.
So one will not see infinite loops in such cases anymore.Regards.
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Radovan Omorjan 30.09.2010 09:05:00
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