Function as variable for another function

Function as variable for another function - Is it possible to use function as variable for function if in this functon is if statement.. - Сообщения

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#1 Опубликовано: 27.09.2020 17:24:11

Rihards

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is it possible to add function as argument to another function if in that function is if statement?

#2 Опубликовано: 27.09.2020 17:41:02

Alvaro Diaz Falconi

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I guess that you have an unit issue, instead to ask "x=1" try with "x=1*'m".
Best regards
Alvaro.

#3 Опубликовано: 27.09.2020 17:51:46

Rihards

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I guess that you have an unit issue, instead to ask "x=1" try with "x=1*'m".
Best regards
Alvaro.

no i tried with out any units.. as far as i can tell its if there is if in the function i cant use it as argument for another function even if it plots perfect as i imagine..

so i played around even further:
it seems that: i can make boolean operations with x and i can use if if x is not evaluated.. but if in if statement there is x then it shows that x is not defined.? is this bug?

#4 Опубликовано: 27.09.2020 19:46:38

Alvaro Diaz Falconi

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This is an "if-issue". It can't be integrate, nor derivate (sometimes) and also can't be called in this way. As workaround use cases.