Hi All,

Could you direct me how to plot the function for some range?

plot in range.sm (5 KiB) downloaded 30 time(s).




Best regards,
Astroneus

Speed graph

Phisic.sm (6 KiB) downloaded 39 time(s).

X_Y plots f(x,y)

Hi,
It looks like that both solution are not what I want to get - especially the first one...
Is there any possibility simply to plot the chart where on Y-axis I simply put the a(t) and on x-axis time??? Because this what you proposed it looks tricky and there is necessity to control units. Therefore it is not intuitive ( at least for me ;P )

Please check the photo below made by ptc mathcad. This what I want to do, is to write the same as the function and plot it using the SMath.




Regards,
Mateusz

In your conditions, only the speed and deceleration time are set.
Therefore a =const.Perhaps there are additional conditions
which you are not reporting.

Wrote

Please check the photo below made by ptc mathcad. This what I want to do, is to write the same as the function and plot it using the SMath.

If that plot is what you need, here is your answer.
With function, dots for values and new axes grid {0.05, -2}.

Regards

plotting_range.sm (10 KiB) downloaded 36 time(s).

Hi Ber7,
This the acceleration during the breaking from 30km/h to zero in linear movement. Therefore in fact there is a(t)= v(t)/t. So: a_i= v_i / t_i and this is function where t is in some range, and i is the iterative change of time ie. the position of specific time. This what you wrote, is not the function of acceleration versus time.

Regards,
Mateusz

@ Jean Giraud and @overload Thank you !

This is what I wanted to write in SMath!

Mateusz

Wrote

this is function where t is in some range

Make your deceleration as you wish from a pre-selected vector 'a'.

Wrote

This is what I wanted to write in SMath !

Differently convenient plot ...

plotting_range [1].sm (11 KiB) downloaded 58 time(s).

Hi. I agree with Ber7 that in absence of any other information the deceleration is constant. Physically that's means that the force of the breaks is constant too, which seems to be a good approximation, neglecting friction forces and some torque considerations about the wheels.

Wrote

Hi Ber7,
This the acceleration during the breaking from 30km/h to zero in linear movement. Therefore in fact there is a(t)= v(t)/t. So: a_i= v_i / t_i and this is function where t is in some range, and i is the iterative change of time ie. the position of specific time. This what you wrote, is not the function of acceleration versus time.

Regards,
Mateusz

Yes it is: a(t) = constant for t in the interval 0 .. 10 s.

Best regards.
Alvaro.

Wrote

@ Jean Giraud and @ overlord Thank you !
This is what I wanted to write in SMath!

At this point, we can populate conveniently
then, pass Thiele continued fraction
and inspect for the first/2nd derivative.
I doubt you can do that in Mathcad/PTC
Cheers ... Jean