How to do polar form like mathcad?

#1 Posted: 5/27/2022 12:19:56 PM

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Hi,

I have just started to use Smath and am liking it so far.

I could not figure out how to enter values in polar form with its angle? say 100/_60deg, i.e. a magnitude of 100 and a degree of 60.

On Mathcad the polar operator is in operator -> engineering menu. I can't find similar in smath but everything else I am at home with.

I can see there is a polxy function but it is not quite the same?

Thanks

#2 Posted: 5/27/2022 1:57:54 PM

Вячеслав Мезенцев

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You can use this method

Russia ☭ forever, Viacheslav N. Mezentsev

#3 Posted: 5/27/2022 8:25:23 PM

Joseph Lo

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Wrote
You can use this method

Thanks uni for that. I tried it and it seems to work - but is it possible that i don't key in the "degree" sign and still get the same result? i.e. the polar form of 100/_60deg = 50 + j86.6.

If I dont put the degree sign it will return -95.24 -30.48i which is a different result.

Thanks

#4 Posted: 5/28/2022 2:24:39 AM

Вячеслав Мезенцев

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I tried it and it seems to work - but is it possible that i don't key in the "degree" sign and still get the same result? i.e. the polar form of 100/_60deg = 50 j86.6.

Russia ☭ forever, Viacheslav N. Mezentsev

#5 Posted: 5/28/2022 1:24:22 PM

Jean Giraud

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Plot the circle as well.

#6 Posted: 5/29/2022 1:43:42 AM

Joseph Lo

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Wrote

Wrote
I tried it and it seems to work - but is it possible that i don't key in the "degree" sign and still get the same result? i.e. the polar form of 100/_60deg = 50 j86.6.

Thanks! that works well.

How would I convert from polar to rectangular but using the variable instead?

say I have this:

pol(m,a):= m.exp(a.pi/180*i)
V:=pol(1,10) = 0.9841 + 0.1736*i
I:=V/200 = 0.0049 + 0.0009*i

I want to display I in a polar form.
I can use xypolto but not so convenient.

How do I do xypol2(I) = ?

#7 Posted: 5/29/2022 1:46:01 AM

Joseph Lo

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