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solve & roots with units - Сообщения
WroteI can it solve in Mathcad - see please mcdx and pdf files
I try solve it (heat transfer) in SMath - see sm file
Help please
SMath symbolic solving of integration is not capable as Mathcad.
Thus integrals can't be used with numeric solvers.
However, you can use a little trick to solve them.
Using maple or maxima plugins is the key.
Here is your problem solved with various ways, roots() and Findroot().
Regards
solvewithunits.sm (23 КиБ) скачан 193 раз(а).
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Hi. The attached have an al_nleqsol wrapper for a Mathcad block with units, that can accept SMath's integrals too.

Kerimov-Cvetkov-Velichko-1-7 - nSol.sm (17 КиБ) скачан 191 раз(а).
Best regards.
Alvaro.
Kerimov-Cvetkov-Velichko-1-7 - nSol.sm (17 КиБ) скачан 191 раз(а).
Best regards.
Alvaro.
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Hello Valery,
In some application(s), you can associate FindRoot with epsilon.
Solve Diophantine Chemical Balance epsilon.sm (106 КиБ) скачан 174 раз(а).
In some application(s), you can associate FindRoot with epsilon.
Solve Diophantine Chemical Balance epsilon.sm (106 КиБ) скачан 174 раз(а).
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Valery Ochkov 05.06.2023 11:26:00
Please help, why can't find root for this simple equation?
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root.sm (20 КиБ) скачан 177 раз(а).
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root.sm (20 КиБ) скачан 177 раз(а).
WrotePlease help,
why can't find root for this simple equation ?
roots solves wrt scalar function(s)
In this example, both functions are scalar wrt 'x'.
Try ... roots[(sin(x)-Gamma(x),x,1]
'x not defined' ... Gamma(x) is not scalar wrt 'x'
Few more numerical functions are not scalar
erf(x), erf(x,n) ... erfc(x), erfc(x,n) ...
WroteTry ... roots[(sin(x)-Gamma(x),x,1]
In that case and similar ones,
RootSecant algorithm will spits out 15 decimals, instantaneous.
Cheers ... Jean.
WroteWrotewhy can't find root for this simple equation?
Because there aren't unknows
Thanks Davide.
Now I put "N" as unknown in the Eq. But it can't be solved either.

root.sm (19 КиБ) скачан 161 раз(а).
You have to play a little with the precision, especially if there are units involved; in this case, seems that 10^-3 mm is a stable target (10^-2 works too, but in some case it returns the guess value, meaning that is "close enough" for the algorithm - you can see in the plot that 0kN to 200kN is in +0.02/-0.02mm range)
![2023-06-26 15_55_45-SMath Solver - [root_r1.sm].png](/ru-RU/files/Download/KcnuBb/2023-06-26-15_55_45-SMath-Solver---[root_r1.sm].png)
root_r1.sm (24 КиБ) скачан 176 раз(а).
![2023-06-26 15_55_45-SMath Solver - [root_r1.sm].png](/ru-RU/files/Download/KcnuBb/2023-06-26-15_55_45-SMath-Solver---[root_r1.sm].png)
root_r1.sm (24 КиБ) скачан 176 раз(а).
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netsonicyxf 26.06.2023 12:18:00
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